Aradio is giving away tickets to a play. they plan to give away tickets for seats that cost $10 and $20. they want to give away at least 20 tickets. the total cost of all the tickets they give away can be no more then $280

The system of inequalities representing the situation are

x + y ≥ 20

10x + 20y ≤ 280

Step-by-step explanation:

Let x represent the number of $10 tickets that the radio station is giving away.

Let y represent the number of $20 tickets that the radio station is giving away.

They want to give away at least 20 tickets. This means that

x + y ≥ 20

The total cost of all the tickets they give away can be no more then $280. This means that

10x + 20y ≤ 280

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

d≈7.07in

step-by-step explanation: