How many four-digit numbers are there formed from the digits 1, 2, 3, 4, 5 (with possible repetition) that are evenly divisible by 4?

80 four-digit numbers are there which is divisible by 4.

Step-by-step explanation:

Consider the provided information.

A number is divisible by 4 if the last 2 digits are divisible by 4.

So the possible last 2 digits are:

xx12, xx24, xx32, xx44, xx52

In each case, for first two number we have 4 choices and last 2 choices are fixed.

Therefore, the total number of ways are: 5(4×4)

Where 5 represents possible case in which last 2 digits are divisible by 4.

the total number of ways are: 5(4×4)=80

Hence, 80 four-digit numbers are there which is divisible by 4.

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

answer:

step-by-step explanation: