The sum of the digits of a two-digit number is 14. when the digits are reversed, the new numbers is 36 more than the original number. what is the original number?

explain the steps too.

The number is 59

Step-by-step explanation:

Let the two digit number be qr.

According to question, q + r = 14

The digits that add to 14 are

1) 59

2) 68

3) 77

4) 86

5) 95

Now,

The reverse of qr is rq.

According to question, rq = 36 + qr

The digit qr cannot be 68,77,86 or 95 because adding 36 to it will result to 3 digit number.

So, qr is 59.

rq = 36 + qr

95 = 36 + 59

x = -2

y = 848

step-by-step explanation:

plug in the numbers

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.