Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean μ = 268 days and standard deviation σ = 18 days. Interpret this probabilityInterpret this probability

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

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the workers who do no drive has no reasonable reason to buy gasoline due to they don't have anything to use it for

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