Fred begins walking toward johns house at 3 miles per hour. john leaves his house at the same time and walks towards fred’s house on the same path at a rate of 2 miles per hour. how long will it take before they meet if their houses are 4 miles apart?

It takes hours or 48 minutes before they meet if their houses are 4 miles apart

Solution:

Let "t" be the number of hours it will take them to meet

Walking speed of Fred = 3 miles per hour

Walking speed of John = 2 miles per hour

Distance between their house = 4 miles

Distance is given by formula:

Distance = speed x time

Fred distance = walking speed of Fred x time taken

Fred distance = 3t

John distance = walking speed of John x time taken

John distance = 2t

Therefore,

3t + 2t = 4

5t = 4

hours

We know that,

1 hour = 60 minutes

Therefore,

Thus it takes hours or 48 minutes before they meet

deez nu tz

step-by-step explanation:

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37