What is the equation of the line parallel to 3x + 5y = 11 that passes through the point (15,4)?

Step-by-step explanation:

3x + 5y = 11

5y = - 3x + 11

y =  -3x/5 + 11/5

Slope = -3/5

The required line is parallel to this line,  So required line's slope= -3/5

(15,4)

y-y1 = m(x-x1)

y - 4 = -3/5 (x - 15)

y -4 = -3x/5 + 15*3/5

y - 4 = -3x/5 + 9

y = -3x/5 + 9 +4

y = -3x/5 + 13

ιт ιѕ $222.95

step-by-step explanation:

αℓℓ уσυ gσт тσ ∂σ ιѕ fιgυяє συт ωнαт 30% σf $318.50 ιѕ $95.55

тнєи ѕυвтяα¢т ιт fяσм $318.50-$95.55=$222.95

нσρє ι ¢συℓ∂ нєℓρ уσυ συ

the correct answer is the last option