Number 40 the challenge question is giving me problems
can anyone me with this question

2

Step-by-step explanation:

Get ready, we are about to get big brain.

So, to solve this problem that I'm probably over-complicating, we have to actually find an equation to represent the missing digit. Now we know that for the fraction, the digit is in the tens place. This means that its real value is ten times more than the 6.

?6/125 - The missing digit is ten times more than the ones place.

It actually turns out that the real value of the missing digit is 10x, with x being the missing digit. Think about it. For example, if the number was 53, then the 5 would be worth ten times more than the 3. You can think of it like this:

(5*10)+(3*1)=53

Now, plugging in our equation

?6/125 becomes (10x+6)/125

Moving on to the other side, we can do something similar. The missing digit becomes represented by the expression 0.1x, because it is in the tenths place. For example, the decimal 0.25:

(2*0.1)+(5*0.01)=0.25

Notice that for our problem, the second digit is actually 100 times smaller. So, it becomes like this:

(x*0.1)+(8*0.001)=0.?08

The problem can now be written as an equation!

(10x+6)/125 = 0.1x+0.008

All we have to do is solve it.

10x+6=12.5x+1 "Multiplying both sides by 125"

6=2.5x+1 "Subtracting 10x from both sides"

5=2.5x "Subtracting 1 from both sides."

2=x "Dividing by 2.5 from both sides."

2 is the mystery digit!

lol

step-by-step explanation:

4th option is correct xy=-10

if this was to u plzz mark me the brainliest