Li na is going to plant 63tomato plants and 81 rhubarb plants.
li na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.
what is the greatest number of rows li na can plant?

The greatest number of rows Li Na can plant is 9

Given that Li Na is going to plant 63 tomato plants and 81 rhubarb plants

Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants

To find: greatest number of rows Li Na can plant

To find the greatest number of rows of plants we have to list the factors of 63 and 81 and find the greatest common one

The factors of 63 are: 1, 3, 7, 9, 21, 63

The factors of 81 are: 1, 3, 9, 27, 81

Then the greatest common factor of 63 and 81 is 9

Thus greatest number of rows Li Na can plant is 9

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.