Molly has 20ml of a 20% sulfuric acid solution and she is mixing it with a 5% sulfuric acid solution. how many millimeters of 5% sulfuric solution must she add in order to end up with a 12% sulfuric acid solution. round answer to nearest millimeter.

Molly has to add 22.86 milliliters of 5% sulfuric acid.

Step-by-step explanation:

Molly has a mixture of 20 ml of 20% sulfuric acid solution.

She mixes this with 5% sulfuric acid solution and in the end she wants a 12% sulfuric acid solution.

We have to find how many milliliters of 5% sulfuric acid we have to add to make it 12% solution.

Let the volume we add be v milliliters.

We are going to equate sulfuric acid.

v = milliliters

v = 22.86 milliliters

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.