4x+2y=4,x-3y=15 how would u substitute this equation for both?

By using the substitution method, the equation solved and get the values of x and y as x = 3 and y = - 4

Step-by-step explanation:

Given equations are:

                   4 x + 2 y = 4         ……….(1)

                    x - 3 y = 15         …………(2)

Now, use the substitution method to solve the given two equations. Multiply equation 2 by 4 on both sides, we will get

                     4 x - 12 y = 60     ……..(3)

Now, subtract equation 1 from equation 3, we get

             (4 x + 2 y) - (4 x - 12 y) = 4 - 60

             14 y = - 56

             y = - 4

Hence, from the above equation, we get the value of y.

Now, we put the value of y in equation 2, we get

                    x - 3(-4) = 15

                    x + 12 = 15

                    x = 3

Hence, the value of x and y by using the substitution method as,

                              x = 3 and  y = - 4

it has changed from the width and the height.

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: