Acar leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. the distance of the car from the stop sign, d d , in feet, at time t t , in seconds, can be found using the equation d=1.1 t 2 d=1.1t2 . what is the average speed of the car, in feet per second, between t=2 t=2 and t=5 t=5 ? 5.5 6.6 7.7 8.5

Option C.

Step-by-step explanation:

The distance of the car from the stop sign, d , in feet, at time t , in seconds, can be found using the equation

The average rate of change of a function f(x) on [a,b] is

We need to find the average speed of the car, in feet per second, between t=2 and t=5.

At t=2,

At t=5,

The average speed of the car, in feet per second, between t=2 and t=5 is

The average speed of the car, in feet per second, between t=2 and t=5 is 7.7 feet per second.

Therefore, the correct option is C.

90% rotation

step-by-step explanation:

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490