Janell is standing on a set of bleachers and throws a ball into the air at an initial velocity of

35 ft/s. the height of the ball, h, at 1 seconds is modeled by the equation h = -162 +35t + 6

how many seconds will it take the ball to reach the ground

The time taken to reach ground is 3.45 sec

Step-by-step explanation:

Given as :

Distance of ball = h = -162 + 35t + 6  at t = 1 sec

The speed of ball thrown  = 35 ft per sec

Let the Time taken to reach ground = T sec

So Time =

Or, Time =

Now distance h at t= 1 sec ,

h = -162 + 35t +6

or,   h = - 162 + 35(1) + 6

So,  h = - 121  feet

Or   = 121 feet

Or, Time =

Or,  Time = 3.45 sec

Hence The time taken to reach ground is 3.45 sec  Answer

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

i believe that the answer is

b. y-1=-2(x-4)

hope this !