This will be similar as in part 2, except we have extended your starter code to apply a "slow" hash. this time the passwords will be hashed by composing sha256 with itself 50 times in a row. additionally, the salt will consist of one digit(0-9). your job is again to find the underlying passwords. again, in this case, the salt is prepended to the password. an example test case is

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

hi how are you doing today? if you ever need just tell me

step-by-step explanation:

after going and makeing graphs i would go with a,

there is nothing that is matches the graph. if there was i would show you. but therefore my answer is a.

hope i

-lavira: )