At t=0, an object of mass m is at rest at x=0 on a horizontal, frictionless surface. a horizontal force fx=f0 (1−t/t), which decreases from f0 at t=0 to zero at t=t, is exerted on the object. part a find an expression for the object's velocity at time t.

v = Fo(1-T)/m

Step-by-step explanation: shown in the attachment

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc