Kalei is 6ft tall and stands 10 feet from a tree. he measures an angle if elevation of 30° up to the coconuts on the tree. how high are the coconuts? round your answer to the nearest tenth.

The total height of coconut Tree = H + 10ft = 11.77 ft

Step-by-step explanation:

Given as,

The height of Kalei = 6ft

The distance of Kalei from the coconut Tree = 10 feet

Angle of elevation of kalei up to the coconut on tree = 30°

Note : look at the pic attache

From figure it is mention that

Total height of Tree = 6 ft + H

So, Tan 30° =

     Tan 30° =

    ∴ H         = 10 Tan 30° = 10 × 0.577         Note : tan 30° = 0.577

i.e    H         = 5.77 ft

Hence the total height of coconut tree = 6 + 5.77 = 11.77 ft   Answer

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150