The angle 0 is located in quadrent 4 and cos(0) = 9/19. what is the value of sin(0)

sin(0) = (-2 sqrt of 70) / 19

Explanation:

Cos = adjacent / hypotenuse

Sin = opposite / hypotenuse

so, using the pythagorean theorem ( a^2 + b^2 = c^2

opp^2 = adj^2 - hyp^2

opp^2 = 9^2 - 19^2

opp^2 = 81 - 361

opp = sqrt of -280

sqrt of 280 can be rewritten as -2 sqrt 70

So, opp = -2 sqrt 70

Sin = opp / hyp

Sin = (-2 sqrt 70) / (19)