Find the solution of the square root of the quantity of x plus 3 plus 6 equals 9 and determine if it is an extraneous solution. ( a. x=0 extraneous; b. x=0 non-extraneous; c. x=6 extraneous; d. x=6 non-extraneous)

√(x+3)+6=9
minus 6 both sides
√(x+3)=3
squar both sides
x+3=+/-9
minus 3 both sides
x=6 or -12

sub to see
√(6+3)+6=9
√(9)+6=9
3+6=9
9=9
true

other one
√(-12+9)+6=9
√(-9)+6=9
false (means this is an extranious answer)

x=6 and it is not extranious
D

72 is anres

The answer is something i don’t know