After first entering the ocean, a scuba diver descends to a depth 18 feet below the surface of the water. The diver then ascends 7 feet before descending 18 feet again. What is the final depth of the diver below the surface of the water?

The diver is 29 ft below the water surface

Step-by-step explanation:

Here, we are interested in calculating the diver’s final depth before the surface of the water.

Firstly he descends 18 feet before ascending 7 feet. His depth would thus be;

18ft -7ft = 11 ft initially

It is at this point he descended a further 18 feet which makes his total feet of descent = 11 ft + 18 ft = 29 ft

This means he is 29 ft below the surface of the water

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;