An article in the journal of sports science (1987, vol. 5, pp. 261-271) presents the results of an investigation of the hemoglobin level of canadian olympic ice hockey players. a random sample of 20 players is selected and the hemoglobin level is measured. the resulting sample mean and standard deviation(g/dl) are and use this information to calculate a 95% two-sided confidence interval on the mean hemoglobin level and a 95% two-sided confidence interval on the variance. assume the data are normally distributed. round your answers to 2 decimal places.

The 95% confidence interval for the population variance is

The 95% confidence interval for the population mean is

Step-by-step explanation:

To solve this problem, a confidence interval of for the population variance will be calculated.

Then, the confidence interval for the population variance is given by:

Thus, the 95% confidence interval for the population variance is:

On other hand,

A confidence interval of for the population mean will be calculated

\Thus, the 95\% confidence interval for the population mean is:

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

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