Vector a has a magnitude of 6.00 units and is directed at 60° to the positive x-axis. vector b has a magnitude of 6.00 units and is directed at 120° to the positive x-axis. find the magnitude and direction of vector c such that a+b+c=0. place the three vectors so that one begins where the previous ends. what do you observe?

C has a magnitud of 10.4 units and is directed 270° from the positive x-axis

Step-by-step explanation:

As it shows on the attached picture, the xA and xB have equal magnitudes but opposite directions, therefore they cancel eachother out in the x-axis.

However, the yA and yB are equal in magnitud, but have the same direction. So, the create a total vector the is completely on the y-axis and it's magnitude is 2*(sin(60°)*6)=10.4 units.

In order for C to cancel this vector, it's magnitude also needs to be 10.4 units, but pointing the other way. Therefore, the angle needs to be 270° from the positive x-axis.

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

where are the images of the functions i can only see the question you typed.

step-by-step explanation: