Suppose two dice (one red, one green) are rolled. consider the following events. a: the red die shows 1; b: the numbers add to 4; c: at least one of the numbers is 3; and d: the numbers do not add to 9. express the given event in symbolic form. hint [see example 5.]
either the numbers add to 9 or the red die shows a 1.
d ∩ b
d ∩ a
d' ∪ a
d' ∩ a
d' ∪ b
how many elements does it contain?

Third option is correct.

Step-by-step explanation:

Since we have given by

Event A: the red die shows 1

Event B :  the numbers add to 4

Event C: at least one of the numbers is 3

Event D : the numbers do not add to 9.

D' means the number add to 9.

We need to write the following statement in symbolic form:

Either the numbers add to 9 or the red die shows a 1.

So, it becomes,

Number of elements in D'∪A = 1.

Hence, Third option is correct.

you cant answer this dummy

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.