In △abc, m∠a=72
△
a
b
c
,
m
∠
a
=
72
°, c=61
c
=
61
, and m∠b=16
m
∠
b
=
16
°. find the perimeter of the triangle.

135.86≈ 136

Step-by-step explanation:

As Given in figure 1:

In ΔABC, m∠A = 72°, m∠B = 16° and c = 61 , where a, b, and c are lengths of side of ΔABC.

To find: Perimeter of triangle = ?

Sol:  In ΔABC,

m∠A + m∠B + m∠C = 180° (sum of angles of a triangle)

m∠C = 180° - (72° + 16°)

m∠C = 92°

Now Using Sine Rule:

Now,

∴

In the same way,

∴

Therefore, a = 58.07 ≈ 58, b = 16.79 ≈ 17 and c = 61

Now, Perimeter of ΔABC = a + b + c = 58 + 17 + 61 = 136  

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x