Asurvey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. the accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader. use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). is the test two-tailed, left-tailed, or right-tailed? left-tailed test two-tailed test right tailed test what is the test statistic? (round to two décimal places as needed.) what is the p-vahie?

Answer with explanation:

Let  p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.

i.e.

Then , the set of hypothesis will be :-

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size :

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader :



The test statistic for proportion is given by :-

By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value =

yes

step-by-step explanation:

yes

you just switch the numbers basically so it would be 3/17