Connor is constructing square abcd. he has plotted a at (−2, 4), c at (−1, 1) and d at (−3, 2). which coordinate could be the location of point b?
a (0, 3)
b (0, 0)
c (1, 1)
d (−1, 2)

The coordinates of the location of point B are (0 , 3) ⇒ answer A

Step-by-step explanation:

* Lets revise some facts

- In the square the diagonals bisect each other, that means they meet

 each other at their mid-point

- In square ABCD , AC and BD are its diagonal

- AC and DB intersect each other at point M where M is the midpoint of

 AC and BD

- The rule of the midpoint of the line whose endpoints are (x1 , y1) and

 (x2 , y2) is

∵ A = (-2 , 4) and C = (-1 , 1)

∵ M is the mid-point of AC

∴

- M is also the mid point of BD

∵ D = (-3 , 2) and M = (-1.5 , 2.5)

- Let B = (x , y)

∵ -1.5 = (x + -3)/2 ⇒ multiply both sides by 2

∴ -3 = x + - 3 add 3 to both sides

∴ 0 = x

∴ The x-coordinate of B is 0

∵ 2.5 = (y + 2)/2 ⇒ multiply both sides by 2

∴ 5 = y + 2 subtract 2 from both sides

∴ 3 = y

∴ The y-coordinate of B is 3

∴ B = (0 , 3)

* The coordinates of the location of point B are (0 , 3)

4x and 6y

im not sure though

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.