Apoint on the terminal side of an angle theta is given. find the value of the indicated trigonometric function of theta. given (-4,-1), find sec(theta)

-√17/4

Step-by-step explanation:

Because both the x- and the y-coordinates of (-4, -1) are negative, the angle, theta, is in Quadrant III.  

tan theta = opp/adj = vertical side / horizontal side = 4/1, or just 4.  

The two coordinates are the legs (both shorter than the hypotenuse) of the triangle formed by this terminal side / point.  

The length of the hypotenuse is found using the Pythagorean Theorem and is:

  √[ (1)² + (4)² = √17.

Again remembering that our terminal side is in Quadrant III,

sin Ф = opp/hyp = -1/√17

cos Ф = adj/hyp = -4/√17

tan Ф = opp/adj = 4 (see discussion above)

The instructions are to "find sec(theta)."  The sec function is the inverse of the cos function.  Here cos Ф = -4/√17, and so the secant of this angle is

the inverse (reciprocal) of the cosine, and is thus   -√17/4

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

the olimpics is not going to wokk out

step-by-step explanation: