Given the numbers x = a and y = –b, which statement is true? a. |x| = –a and –|y| = –b b. –|x| = a and –|y| = b c. |–x| = –a and |–y| = b d. |x| = a and |y| = b

choice D is correct, any number inside the absolute value sign is positive so choice A and C is eliminated, if there is a negative sign in front of the absolute value symbol, the number becomes negative which eliminates choice B. The only choice left is choice D

D. |x| = a and |y| = b , because modulus sign (| |) turns a negative number into positive

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents