The heights of all adult males in croatia are approximately normally distributed with a mean of 180 cm and a standard deviation of 7 cm. how tall must an adult male in croatia be in order to be the tallest 5% of the males

In standard normal distribution, the cutoff for the 95th percentile is about . So the cutoff height would be such that

cm.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

it's undefined because anything multiplied by 0 is 0. that said, 7 days is 168 hours