I need help on this? Can anyone help me on it?

Step-by-step explanation:

ooooh I loved these.  ok. so if you have a set of lines like this, we will just use an "x" as an example for lines crossing. if you have 100 as the angle on the top, then the angle on the bottom will be exactly the same. the top and bottom are the same angle ALWAYS. the angles across from each other are the same. because will timeout on me if I stop typing, I will post this and later I will post a picture of the first few finished as an example so you get what i'm talking.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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