Eight algebra questions (explanations would be appreciated):

use substitution to solve the following:

1)
y=x²
y=x+2

2)
y=x²+3
y=4x

3)
x²+4y=1
y=x+1

4)
x²-3y=-2
y=4+x

5)
x²-2y=-4
y=6-x

6)
x²+4y=9
y=x-3

7)
x²+5y=16
y+x=2

8)
y=x²-6x
3x-y=-10

Step-by-step explanation:

1)  

y=x²

y=x+2

so: x² = x+2

x²-x-2 = 0

(x+1)(x-2)=0

x+1=0 or x -2=0

x =-1 or x=2

x= - 1   y = -1+2 =1

x= 2   y=2+2=4

continu   same method

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

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