calculate the mean of the following data set: $68.50, $69.87, $70.10, and $70.40.

a. $69.60
b. $68.50
c. $69.87
d. $70.40

my answer is C  $69.87

Step-by-step explanation:

my answer is C  $69.87

Step-by-step explanation:

Mean = $69.72

Step-by-step explanation:

Calculate the mean of the following data set: $68.50, $69.87, $70.10, and $70.40.

= ($68.50 +  $69.87 +  $70.10 + $70.40)/4

= $278.87 / 4

= $69.7175

= $69.72

Mean = $69.72

I don't see it matches any of your answers.

Mean = $69.72

Step-by-step explanation:

Calculate the mean of the following data set: $68.50, $69.87, $70.10, and $70.40.

= ($68.50 +  $69.87 +  $70.10 + $70.40)/4

= $278.87 / 4

= $69.7175

= $69.72

Mean = $69.72

I don't see it matches any of your answers.

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.