Mathematics

Mathematics, 21.06.2019 22:30, Bt758

What is the point slope form of a line with slope -5 that contains point (2,-1)

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Mathematics, 01.07.2019 09:00, andreanaapollon6337

What is the equation in point slope form of a line that passes through the point (−8, 2) and has a slope of 1/2 ? drag a number, symbol, or variable to each box to write a point-slope equation for this line. (will give brainliest to correct answer)

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Mathematics, 16.07.2019 09:00, arod20061

The figure shows a line graph and two shaded triangles that are similar: which statement about the slope of the line is true? a-it is 3 throughout the line b-it is 1/3 throughout the line c- the slope from point o to point a is fraction 1/3 time the slope of the line from point a to point b d-the slope from point o to point a is 3 times the slope of the line from point a to point b.

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Mathematics, 18.07.2019 16:30, espemena541

The figure shows a line graph and two shaded triangles that are similar: which statement about the slope of the line is true? it is fraction 1 over 2 throughout the line. it is 2 throughout the line. the slope from point o to point a is fraction 1 over 2 time the slope of the line from point a to point b. the slope from point o to point a is two times the slope of the line from point a to point b.

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Mathematics, 24.07.2019 15:40, haileycrane

Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the graph of 3x + 2y = –11. his work is shown below. 1. 3x + 2y = –11 written in slope-intercept form is y = -3/2x - 11/2 , so the slope is -3/2. 2. the slope of the perpendicular line is -2/3. 3. substitute the point and the new slope into point-slope form to get y – 5 = -2/3(x – (– 4. simplifying, the line is y – 5 = -2/3(x + 6). is simon’s work correct? a. no, the slope of the line 3x + 2y = –11 is not . b. no, the slope of the line perpendicular to the line 3x + 2y = –11 should be . c. no, he did not substitute the point and the slope into point-slope form correctly. d. yes, the work is correct.

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