Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the graph of 3x + 2y = –11. his work is shown below. 1. 3x + 2y = –11 written in slope-intercept form is y = -3/2x - 11/2 , so the slope is -3/2. 2. the slope of the perpendicular line is -2/3. 3. substitute the point and the new slope into point-slope form to get y – 5 = -2/3(x – (– 4. simplifying, the line is y – 5 = -2/3(x + 6). is simon’s work correct? a. no, the slope of the line 3x + 2y = –11 is not . b. no, the slope of the line perpendicular to the line 3x + 2y = –11 should be . c. no, he did not substitute the point and the slope into point-slope form correctly. d. yes, the work is correct.

B. No, the slope of the line perpendicular to the line 3x + 2y = –11 should be 2/3.

Step-by-step explanation:

The slope of a perpendicular line is the opposite of the reciprocal of the slope of the original. Simon correctly computed the original line's slope to be -3/2. He correctly computed the reciprocal of that to be -2/3, but failed to recognize that the slope of the perpendicular line is the opposite of this, 2/3.

Simon's work is correct otherwise.

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

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step-by-step explanation:

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