Quick the sum of four consecutive integers is 130 what is the third number in the sequence 20 points

33

Step-by-step explanation:

1st integer =x

2nd integer = x+1

3rd integer = x+2

4th integer = x+3

sum of four consecutive integers is 130

x+(x+1)+(x+2)+(x+3) = 130

Combine like terms

4x+6 = 130

Subtract 6 from each side

4x+6-6 = 130-6

4x = 124

Divide by 4

4x/4 = 124/4

x=31

Find the third number

x+2 =31+2 = 33

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

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btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )