Degree 5; zeros: -2, i, -2i find the remaining zeros

-i and 2i

Explanation:

Degree 5 means you will have 5 roots.

Real          Complex       Conjugate

 5  

                        i                   -i

                     -2i                   2i

Roots:

x = 5

x = i , x = -1

x = -2i,  x = 2i

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

definitely a. the others have almost all data points on one side of the line.

step-by-step explanation: