Five chips numbered 1 through 5 are placed in a bag. a chip is drawn and replaced. then a second chip is drawn. find the probability that one chip is even and the other is odd. (hint: you can choose an even chip and then an odd chip, or an odd chip and then an even chip.)

There are 3 odd and 2 even numbers involved here.

So Prob( even then odd) = 2/5 * 3/5 = 6/25

Pro(odd then even) = 3/5 * 2/5 = 6/25

Therefore  Prob( either of the above) = 6/25 + 6/25 = 12/25 (answer)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|