Find the equation f(x) = a(x - h)2 + k for a parabola containing point (3, 6) and having (1, -2) as a vertex. what is the standard form of the equation? a) the vertex form is f(x) = 2(x - 1)2 − 2. the standard form is f(x) = 2x2−4x. b) the vertex form is f(x) = 2(x + 1)2 + 2. the standard form is f(x) = −2x2−4x. c) the vertex form is f(x) = −2(x - 7)2− 2. the standard form is f(x) = 2x2 + 4x. d) the vertex form is f(x) = −2(x - 1)2 − 2. the standard form is f(x) = 2x2 +4 x.

the 1 is the h and the -2 is the k

f(x) = a(x - h)^2 + k

f(x) = a(x-1)^2 -2

to find a  substitute x=3, y=6 in

6= a(3-1)^2 -2

6 =a *2^2 -2

add 2 to each side

8 = 4a

a =2

f(x) = 2(x-1)^2 -2  this is the vertex form

distribute to get the standard from

f(x) = 2(x^2-2x+1) -2

    2x^2 -4x+2-2

 f(x) =2x^2-4x   is the standard form

Choice A

associative property of multiplication

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

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