Can anyone me with the odd numbers on my algebra 1 homework?

y =x+10

y =6x+30

substitute x+10 into the 2nd equation anywhere you see y

x+10 = 6x+30

subtract x from each side

x-x+10 = 6x-x+30

10 = 5x+30

subtract 30 from each side

10-30=5x+30-30

-20 = 5x

divide by 5 on each side

-20/5 =5x/5

-4=x

now solve for y

y=x+10

y = -4 +10

y=6

x=-4

y=6

or (-4,6)

3.  y = -3x-6

6x+5y=-30

6x+5(-3x-6) =-30

5x-15x-30=-30

-20x-30=-30

-20x=0

x=0

y = -3x-6

y=-6

(2,9)

i think thats the answer i checked it on google

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square