If (-2, y) lles on the graph of y = 3^x, then y =

We know that , so substitute that into the equation.

With negative powers, instead of making the result negative, you divide one by it.  Mathematically speaking, .  This makes our equation:

Finally, simplify the exponent.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

thats not a system of equations, that is a solution