Trevor ariza is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 70%, percent of the time. what is the probability of trevor ariza making none of his next 5 free throw attempts?

Probability of making none of next 5 free throws = 0.00243

Step-by-step explanation:

"Making or missing free throws doesn't change the probability that he will make his next one"

So the probability of making none of next 5 free throws

= Probability of missing next 5 free throws

= Probability of missing 1 free throw^5

"...he makes his free throws 70%" so the probability of missing 1 free throw = 1-70% = 0.3

So the probability of making none of next 5 free throws = 0.3^5

= 0.00243

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0