Steven rolled a 1-6 number cube four times. What is the proballity that Steven rolled an odd number on all four rolls of
the die? (leave your answer as a reduced fraction)

0.0625

Step-by-step explanation:

From the question, Steven rolled a 1-6 number cube four times. This means the 1-6 number cube has numbers 1, 2, 3, 4, 5 and 6. There are 3 odd numbers which are 1, 3 and 5. If the 1-6 number cube is rolled once, the probability will be:

3/6 = 1/2

Since Steven rolled the 1-6 number cube four times, the probability of getting an odd number on all four rolls of the die will be:

= 1/2 × 1/2 × 1/2 × 1/2

= 1/16

= 0.0625

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.