You want to estimate the mean weight loss of people one year after using a popular weight-loss program being advertised on tv. how many people on that program must be surveyed if we want to be 95% confident that the sample mean weight loss is within 0.25 lb of the true population mean? assume that the population standard deviation is known to be 10.6 lb.

6907 people on that program must be surveyed if we want mean weight loss as 0.25 lb and standard deviation as 10.6 lb.

Step-by-step explanation:

Given that mean of weight loss in 0.25 lb and standard deviation is 10.6 lb.

For 95% confident level z-score must be 1.96.

That is =1.96

Now required sample size is

Where SE means standard deviation=10.6 lb and mean m=0.25 lb

Hence sample size=

Which we always should round up that is 6907.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation: