Find the standard form of the equation of the parabola with a focus ar (0,5) and a directrix at y=-5

So firstly, the focus falls on the line of symmetry (as well as the vertex) and the focus and the directrix are equidistant, or equal distance from, from the vertex. To find the focal length, take the distance from the directrix and the focus and divide it by 2.

In this case, the focus and the directrix are 10 units away, and 10 ÷ 2 = 5. 5 is your focal length.

Now, since the focus is above the directrix, this means that this is a parabola that opens up, and hence the a variable is positive. And to find the vertex, you need to subtract 5 (the focal length) from the y-coordinate of the focus:

The vertex is (0,0). Using vertex form, plug the vertex into it:

Next, we are going to find the a variable. Plug the focal length into the formula I had mentioned earlier to find it:

Plug 1/20 into the equation:

Now that we have our vertex form, we need to convert it into standard form. For this, just foil (x  - 0)^2:

Your final answer is

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

w'x is 0.

hope it