Ido not understand : the vertex form of the equation of a vertical parabola is given by , where (h, k) is the vertex of the parabola and the absolute value of p is the distance from the vertex to the focus, which is also the distance from the vertex to the directrix. you will use the geogebra geometry tool to create a vertical parabola and write the vertex form of its equation. open geogebra, and complete each step below. if you need , follow these instructions for using geogebra. part a ( i already answer it ) mark the focus of the parabola you are going to create at f(6, 4). draw a horizontal line that is 6 units below the focus. this line will be the directrix of your parabola. what is the equation of the line? the parabola is vertical since the directrix is horizontal. the parabola opens upwards, since the focus lies above the directrix. equation of up-opening parabola is in general:  y = a(x - a)² + b the vertex is halfway between focus and directrix. vertex (6, 1) a = 6 b= 1 p = distance between focus and vertex = 3 k= 1/(4p) = 1/12 so the equation of the parabola is : y = (1/12)(x - 6)² + 1 need in this part b: part b: construct the line that is perpendicular to the directrix and passes through the focus. this line will be the axis of symmetry of the parabola. what are the coordinates of the point of intersection, a, of the axis of symmetry and the directrix of the parabola?