Given that sintheta = 6/17, find sectheta me and show work ill be so happy and ill medal

The answer is which is the fraction of 17 over sqrt(253). The notation "sqrt" is shorthand for "square root"

Check out the attached image to see the steps on how I got that answer.

Edit: if you need the steps for the pythagorean theorem, then....

a^2+b^2 = c^2

6^2+b^2 = 17^2

36+b^2 = 289

b^2 = 289-36

b^2 = 253

b = sqrt(253)

So that's how I got the square root of 253 as the adjacent side

10

step-by-step explanation: