Find the values of c such that the area of the region bounded by the parabolas y = 16x2 − c2 and y = c2 − 16x2 is 250/3. (enter your answers as a comma-separated list.)

First, note that these two parabolas are symmetric about the x-axis. The first one has its branches up in y-direction and the second one has its branches down in y-direction. This means that if you want to find area of the region bounded by the parabolas, you can find area of the region bounded by second parabola and x-axis and multiply it by 2.

1. Find x-intercepts of parabola

When y=0, you have

2. Find area:

Then the area of the region bounded by the parabolas is

3. Since this area is you have

c=5.

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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