Given the arithemtic or geometric sequence, identify f(0) and the common difference/ ratio f(x) = f(x-1) multiplied by 6; f(1)=12 f(0)=

Required value of f(0) = 2 and common ratio of given geometric sequence is 6.

Solution:

Given sequence rule for geometric sequence is f(x) = f(x-1) multiplied by 6 that is,

f(x) =6(f(x-1))   .

Also given that f(1) = 12 .

We need to determine f(0) and common ratio.

Calculating f(0) :

On substituting x = 1 in given sequence rule, we get  

f(1) = 6(f(1-1))  

f(1) = 6(f(0))

f(0) =  

Given that f(1) = 12, substituting in above expression we get

so f(0) = = 2  

Calculation common ratio:

On substituting x = 2 in given sequence rule, we get  

f(2) = 6(f(2-1))

f(2) = 6(f(1))

= 6

And is nothing but common ratio.

Hence required value of f(0) = 2 and common ratio of given geometric sequence is 6.

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1