Solve the equation by completing the square. round to the nearest hundredth if necessary. x2 – 3x – 3 = 0

x² – 3x – 3 = 0

First, add 3 to both sides

x² – 3x – 3 (+3)= 0 (+3)

x² – 3x = 3

Solve for a. 2ax = -3x; a = -3/2

x² - 3x + (-3/2)² = 3 + (-3/2)²

Simplify

x² - 3x + (-3/2)² = 21/4

Complete the square

(3 - 3/2)² = 21/4

solve:

x - 3/2 = √(21/4); x = (√21 + 3)/2

x - 3/2 = -√(21/4); x = ((-√21) + 3)/2

Answers:

x = ((√21) + 3)/2 & x = ((-√21) + 3)/2

hope this helps

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

a 90 degree rotation across the the origin followed by a reflection across the x-axis.

step-by-step explanation: