The quality characteristic T depends on X and Y according to the expression T = XeY . X and Y are approximately normally distributed with means 10.0 and 2.0, respectively and standard deviations of 0.1 and 0.05, respectively (so that the natural tolerance limits are 10.0 ± 0.3 for X and 2.00 ± 0.15 for Y ). a) Find the natural tolerance limits for T.

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

boxplot e is the answer

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632