What are the domain range and asymptote of h(x)=6^x-4

The asymptote of the function f(x) = aˣ is y = 0.

The domain of the function f(x) = aˣ is x ∈ R.

The range of the function f(x) = aˣ is y > 0.

-----------------------------------------------------------------------------------

f(x - n) - shifting the graph by n units to the right

f(x + n) - shifting the graph by n units to the left

f(x) - n - shifting the graph by n units down

f(x) + n - shifting the graph by n units up

---------------------------------------------------------------------------

We have

- shifting the graph of f(x) = 6ˣ, 4 units to the right. Therefore

Domain - no change

Range - no change

Asymptote - no change

The asymptote is y = 0. The domain is x ∈ R. The range is y > 0.

If , therefore

- shifting the graph of f(x) = 6ˣ, 4 units down.

Therefore, yor answer is:

Domain - no change (x ∈ R)

Range - change → y > -4

Asymptote - change → y = -4

answer: that was hard but still working on it

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.