Combination/permutation math a cellphone/telephone keypad has keys numbered with the digits 0 to 9, inclusive. each of the keys, except the "1" (one) and "0" (zero) keys, also contains letters. how many different telephone numbers are possible using this keypad, if each "number" consists of two letters followed by five digits, where the first digit is not zero? i know that the answer is 5,760,000 but i dont know how they got this answer. explain in detail and i will give brainliest

This type of combination problem involves combined probability, or the chance that a specific set could be chosen based on the probability of multiple variables.

The number that could be generated follows the example:

XXY

where X describes a letter, and Y describes a number that isn’t zero, and Z describes any number.

Two probabilities exist in this situation, depending on the circumstances of the question. By pressing any number once, only 8 letters can be used (ten digits, minus the one and two keys, since they don’t have letters). This means that the probability of this event is:

8 x 8 x 9 x 10 x 10 x 10 x 10

where the two eights are for the letters, the nine is for the digit that isn’t zero, and the tens are for any numbers from the keypad. This permutation yields 5,760,000 choices.

If you are allowed to press the numbers more than once to generate a letter, then the probability changes to account for the entire alphabet. The new probability of this event is :

26 x 26 x 9 x 10 x 10 x 10 x 10

where this permutation yields 60,840,000 choices.

Hope this helps!

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